5x^2-3x+4=2x^2+5

Solution for 5x^2-3x+4=2x^2+5 equation:

5x^2-3x+4=2x^2+5

We move all terms to the left:

5x^2-3x+4-(2x^2+5)=0

We get rid of parentheses

5x^2-2x^2-3x-5+4=0

We add all the numbers together, and all the variables

3x^2-3x-1=0

a = 3; b = -3; c = -1;
Δ = b2-4ac
Δ = -32-4·3·(-1)
Δ = 21
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{21}}{2*3}=\frac{3-\sqrt{21}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{21}}{2*3}=\frac{3+\sqrt{21}}{6}
$